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A weak base (50.0 mL) was titrated with ...

A weak base (50.0 mL) was titrated with 0.1 M HCl. The pH of the solution after the addition of 10.0 mL and 25.0 mL were found to be 9.84 and 9.24, respectively. Calculate Kb of the base and pH at the equivalence point.

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The correct Answer is:
`K_(e)= 1.8 xx 10^(-5), 5.27`
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