If 0.0005 mol `NaHCO_3` is added to 1 litre of a buffered solution at pH 8.00, how much material will exist in each of the three forms `H_2CO_3, HCO_3^- and CO_3^(2-)` ? For `H_2CO_3, K_1= 5 xx 10^(-7), K_2= 5 xx 10^(-13)`

Answer

`[H_(2)CO_(3)]=9.85 x 10^(-6)M; [HCO_(3)^(-)]=4.9 xx 10^(-4) [CO_(3)^(2-)]=2.45 xx 10^(-4)`