A car accelerates from rest with 2m/s^(2) on a straight line path and then comes to rest after applying brakes.Total distance travelled by the car is 100m in20 seconds then the maximum velocity attained by the car is

A car accelerates from rest with a =2 m//sec^(2) in a straight track, then it comes to rest applying its brakes after a time T 20 seconds covering a distance of 100 m. Using a graphical method, find the maximum speed of the car..

A car accelerates from rest at a constant rate for some time after which it decelerates at a constant rate beta to come to rest. If the total time elapsed is t, the maximum velocity acquired by the car is given by :

A car acceleration from rest at a constant rate 2m//s^(2) for some time. Then, it retards at a constant rate of 4 m//s^(2) and comes to rest. If it remains motion for 3 second, then the maximum speed attained by the car is:-

A car accelerates from rest at a constant rate alpha for sometime , after which it decelerates at a constant rate beta and comes to rest. If T is the total time elapsed, the maximum velocity acquired by the car is

A car accelerates from rest with 2ms^-2 for 2s and then decelerates constantly with 4ms^-2 for t_0 second to come to rest. The graph for the motion is shown in figure. a. Find the maximum speed attained by the car. b. Find the value of t_0 .

A train starts from rest and moves with a constant accelerationof 2.0 m/s^2 for half a minute. The brakes are then applied and the train comes to rest in one minute. Find a. the total distance moved by the train, b. the maximum speed attained by the train and c. the position(s) of the train at half the maximum speed.

A car accelerates uniformly at 4 m s^(-2) from rest. Find its velocity at the end of 5 seconds.

A car accelerates from rest at acionstant rate 36 km h^@ to comet to rest. If the total time elapsed id 1 hour, calculate (i) the maximum velocity attained by the car and (ii) the total distance travelled by car.