Find the integral`int(sqrt(x)-1/(sqrt(x)))^2dx`

Explanation

To solve the integral \(\int \left(\sqrt{x} - \frac{1}{\sqrt{x}}\right)^2 dx\), we will follow these steps:

### Step 1: Expand the integrand
First, we need to expand the expression inside the integral:

\[ \left(\sqrt{x} - \frac{1}{\sqrt{x}}\right)^2 = \left(\sqrt{x}\right)^2 - 2 \cdot \sqrt{x} \cdot \frac{1}{\sqrt{x}} + \left(\frac{1}{\sqrt{x}}\right)^2 \]
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