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For three events A,B and C P(Exactly one...

For three events A,B and C P(Exactly one of A or B C occurs)
=P(Exactly one of B or C occurs)
=P(Exactly one of C or A occurs ) `=(1)/(4)` and P(All the three events occurs simultaneously ) `=(1)/(16)`, Then the probability that atleast one of hte events occurs, is

A

`(7)/(16)`

B

`(7)/(64)`

C

`(3)/(16)`

D

`(7)/(32)`

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The correct Answer is:
A
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