A particle of mass `m` is released in vertical plane from a point `P` at `x=x_(0)` on the `x`-axis. It falls vertically parallel to the `y`-axis. Find the torque `tau` acting on the particle at a time about origin.

Explanation

Torque is produced by the force of gravity

`vectau= r F sin theta hatk` or ` tau = r_(bot) F x_0` mg