A particle having mass m is projected with a velocity `v_(0)` from a point P on a horizontal ground making an angle `theta` with horizontal. Find out the torque about the point of projection acting on the particle when
it is at its maximum height ?

Explanation

Particle is at maximum height then `tau` about point
P is ` tau_p = t_(bot)F`
F = mg , `r_(bot) = R/2`

`rArr tau_p = R/2 mg = mgxx(v_0^2 sin 2 theta)/(2g)`
`tau_p = (mv_0^2sin 2theta)/(2g)`
` tau_p = (mv_0^2 sin 2 theta)/2`