A solid cylinder of mass `20 kg` rotates about its axis with angular velocity of `100` radian `s^(-1)`. The radius of the cylinder is `0.25m`. The magnitude of the angular momentum of the cylinder about its axis of rotation is

Explanation

`M = 20 kg," "w = 100 "rads"^(-1)" "R = 0.25" m"`
Moment of inertia of the cylinder about its axis
`I =1/2 MR^2 = 1/2 xx20xx(0.25)^2 = 0.625 kg - m^2`
Angular momentum
` L - I omega = 0.625 xx100 = 62.5` joule-second