A spherical shell has a radius of 1.90 m. An applied torque of 960 N-m gives the shell an angular acceleration of `"6.20 rad/s"^2` about an axis passing through the centre of the shell. What are
the rotational inertia of the shell about that axis

Explanation

Use `tau = Ia` where `tau` is the net torque acting on the shell, I is the rotational inertia of the shell, and `alpha` as its angular acceleration. This gives
`I=(tau)/(alpha)=(960N.m)/(620"rad"//s^(2))=155 kg-m^(2)`