A rotating table has angular velocity `'omega'` and moment of inertia `I_(1)`. A person of mass 'm' stands on the centre of rotating table. If the preson moves a distance r along its radius then what will be thefinal angualr velcotiy of the rotating table ?

Explanation

To solve the problem, we will use the principle of conservation of angular momentum. The angular momentum of a system remains constant if no external torques act on it.

### Step-by-Step Solution:

1. **Define Initial Conditions:**
- The initial angular velocity of the rotating table is given as \( \omega_1 \).
- The moment of inertia of the rotating table is \( I_1 \).
- The person of mass \( m \) is initially at the center of the table (distance \( r = 0 \)).
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