A sphere of mass `M` rolls without slipping on rough surface with centre of mass has constant speed `v_0`. If mass of the sphere is `m` and its radius be R`, then the angular momentum of the sphere about the point of contact is.

Explanation

`therefore vec(L)_(p)=vec(L)_(cm)+vec(r )+vec(p)_(cm)=I_(cm)vec(omega)+vec(R )xxm vec(v)_(cm)`
here `V_(cm)=v_(0)`
Since sphere is in pure rolling motion
hence `omega = v_(0)R`
`rArr (7)/(5)Mv_(0)R(-vec(k))`