Evaluate `int_(-pi/4)^(pi/4) sin^2xdx`

Explanation

To evaluate the integral \( \int_{-\pi/4}^{\pi/4} \sin^2 x \, dx \), we can follow these steps:

### Step 1: Use the identity for \( \sin^2 x \)
We know that:
\[ \sin^2 x = \frac{1 - \cos(2x)}{2} \]
Thus, we can rewrite the integral as:
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