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Two coils have self-inductance L(1) = 4m...

Two coils have self-inductance `L_(1) = 4mH` and `L_(2) = 1 mH` respectively. The currents in the two coils are increased at the same rate. At a certain instant of time both coils are given the same power. If `I_(1)` and `I_(2)` are the currents in the two coils, at that instant of time respectively, then the value of `(I_(1)//I_(2))` is :

A

`1//8`

B

`1//4`

C

`1//2`

D

`1`

Text Solution

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The correct Answer is:
B
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