" (iv) "16x-(10)/(x)=27

Solve by factorization: 16x-(10)/(x)=27

Solve by factorization: 16 x-(10)/x=27

(16)/(5x)=(1)/(10)

The quadratic equation whose roots are sin^(2)18^(0)&cos^(2)36^(0) is (А) 16x^(2)-12x+1,=0 (В) 16x^(2)+12x+1=0 (C) 16x^(2)-12x-1=0 (D) 16x^(2)-10x-1=0

(16-x)/(x)=(22)/(10)

Solve the equation 64.9^(x)-84(12^(x))+27(16^(x))=0

Solve the equation 64.9^(x)-84(12^(x))+27(16^(x))=0

Solve the equation 64.9^(x)-84(12^(x))+27(16^(x))=0

Solve the equation 64.9^(x)-84(12^(x))+27(16^(x))=0

If 2x-1 is a factor of 4x^(3) - 16x^(2) + 10x + k , find the value of k.