The sum of two forces `vec P` and `vec Q` is `vec R` such that `|vec R|=|vec P|` .The angle `theta` (in degrees) that the resultant of `2vec P` and `vec Q` will make with `vec Q` is

Two vectors vec P and vec Q

What is the angle between vec P and the resultant of (vec P+vec Q) and (vec P-vec Q)

If vec P+ vec Q = vec R and |vec P| = |vec Q| = | vec R| , then angle between vec P and vec Q is

The magnitude of the resultant vec R of two forces vec P and vec Q" is 20 N. "vec R make an angle of 30^(@) with vec P and an angle of 60^(@) with vec Q . What are the magnitudes of vec P and vec Q ?

What is the angle between vec(P) and the resultant of (vec(P)+vec(Q)) and (vec(P)-vec(Q)) ?

The greatest resultant of two vectors vec P and vec Q is (n) times their least reast resultant. Fiven | vec P | gt |vec Q| . When theta is the angle between the two vectors, their resultant is half the sum of the two vectors. Show that, cos theta =- (n^(2) +2) // (n n^(2) -1) .

For three vectors vec p,vec q and vec r if vec r=3vec p+4vec q and 2vec r=vec p-3vec q then

If vec P xx vec Q= vec R, vec Q xx vec R= vec P and vec R xx vec P = vec Q then

If vec P and vec Q are two vectors, then the value of (vec P + vec Q) xx (vec P - vec Q) is

The resultant of two vectors vec(P) and vec(Q) is vec(R) . If vec(Q) is doubled then the new resultant vector is perpendicular to vec(P) . Then magnitude of vec(R) is :-