Home
Class 12
MATHS
Find the area of the circle 4x^2+4y^2=9...

Find the area of the circle `4x^2+4y^2=9` which is interior to the parabola `x^2=4y`.

Text Solution

AI Generated Solution

To find the area of the circle \(4x^2 + 4y^2 = 9\) that is interior to the parabola \(x^2 = 4y\), we can follow these steps: ### Step 1: Rewrite the equations First, we rewrite the equations of the circle and the parabola in a more standard form. The equation of the circle can be simplified: \[ 4x^2 + 4y^2 = 9 \implies x^2 + y^2 = \frac{9}{4} ...
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF INTEGRALS

    NCERT|Exercise SOLVED EXAMPLES|15 Videos

  • APPLICATION OF DERIVATIVES

    NCERT|Exercise EXERCISE 6.1|18 Videos

  • CONTINUITY AND DIFFERENTIABILITY

    NCERT|Exercise QUESTION|3 Videos

Similar Questions

Explore conceptually related problems

Find the area of circle 4x^(2)+4y^(2)=9 which is interior to the parabola x^(2)=4y

Find the area of the circle 4x^2+4y^2=9 which is interior to parabola y^2=4x .

Find the area of that part of the circle x^(2)+y^(2)=16 which is exterior to the parabola y^(2)=6x

Find the equation of the circle which is concentric with the circle x^2 +y^2 - 4x+6y-3=0 and the double of its area.

Find the equation of line which is normal to the parabola x^(2)=4y and touches the parabola y^(2)=12x .

Find the area of the region which is inside the parabola y = - x^(2) + 6x - 5 , out the side the parabola y = - x^(2) + 4x - 3 and left of the stragiht line y = 3x-15 .

Find area of the ellipse 4x ^(2) + 9y ^(2) = 36.

If the circle x^(2)+y^(2)+2ax=0, a in R touches the parabola y^(2)=4x , them

Find the equation of the circle through the points of interrection of the circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+6x+4y-12=0 and cutting the circle x^(2)+y^(2)-2x-4=0 orthogonally.