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Using integration find the area of regi...

Using integration find the area of region bounded by the triangle whose vertices are `( 1, 0), (1, 3) a n d (3, 2)`.

Text Solution

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BL and CM are drawn perpendicular to x-axis.
It can be observed in the following figure that,
`Area(ΔACB)=Area(ALBA)+Area(BLMCB)−Area(AMCA) ......... (1)`
Equating of line segment AB is
`=>y−0=(3−0)/(1+1)​(x+1)`
`=>y=(3/2)​(x+1)`
∴Area(ALBA)`=int_-1^1​(3/2)​(x+1)dx`
...
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