Home
Class 12
MATHS
Verify that the given functions (explic...

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:`y=sqrt(a^2-x^2)x in (-x , a)` : `x+y(dy)/(dx)=0(y!=0)`

Text Solution

Verified by Experts

`y = sqrt(a^2-x^2)`
Squaring both sides,
`=>y^2 = a^2-x^2`
Differentiating both sides w.r.t. `x`,
`=>2ydy/dx = 0 - 2x`
`=>ydy/dx = - x`
`=>x+ydy/dx = 0`
So, given function is a solution of the corresponding differential equation.
Promotional Banner

Topper's Solved these Questions

  • DIFFERENTIAL EQUATIONS

    NCERT|Exercise Miscellaneous Exercise|18 Videos
  • DIFFERENTIAL EQUATIONS

    NCERT|Exercise EXERCISE 9.6|19 Videos
  • DETERMINANTS

    NCERT|Exercise EXERCISE 4.4|5 Videos
  • INTEGRALS

    NCERT|Exercise EXERCISE 7.4|25 Videos

Similar Questions

Explore conceptually related problems

Verify that the given functions (explicit or implicit is a solution of the corresponding differential equation: y=e^(x)+1:y''-y'=0

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation : y=Ax : xy'=y(x ne 0)

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y=sqrt(1+x^(2))y'=(xy)/(1+x^(2))

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y=cos x+Cvdotsy'+sin x=0

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y-cos y=x:(y sin y+cos y+x)y?=y

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: x+y=tan^(-1)yvdotsy^(2)y'+y^(2)+1=0

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: xy=log y+Cvdotsy'=(y^(2))/(1-xy)(xy!=1)

Verify that the given function (explicit of implicit ) is a solution of the corresponding differential equation : (ii) x+y=tan^(-1)y, y^(2)y'+y^(2)+1=0 .

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y" "=" "x" "s in" "x : x yprime=y+xsqrt(x^2-y^2)(x!=0 andx" ">" "y" "or" "x" "<" "" "y )

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: 'y =sqrt(1+x^(^^)2):y'=xy/1+x^(^^)2'yquad =quad Ax:xy'=y(x!=0)