`DeltaABC` एक समद्विबाहु त्रिभुज है की `AB=AC` तथा `angleB=35^(@)` है। AD , भुजा BC पर मधियाका है। `angleBAD` ज्ञात करे?

Options

A. `70^(@)`
B. `35^(@)`
C. `110^(@)`
D. `55^(@)`

Answer

D

Explanation

According to question,

AB=AC, `angleA=angleC`
`angleA+angleB+angleC= 180^(@)`
`angleA+2angleB=180^(@)`
`angleA=180^(@)-70^(@)`
`angleA =110^(@)`
Note: In isosceles triangle median bisects the opposite side and make anlge `90^(@)` on opposite angle .

`angleBAD=angleA/2`
`angleBAD=110^(@)/2=55^(@)`