`DeltaABC` की भुजाओ AC तथा BC पर दो बिंदु D तथा E इस प्रकार है की DE = 18 cm , CE = 5 cm तथा `angleDEC=90^(@)` हो। यदि `tanangleABC=3.6` है, तब `AC:CD=?`

Options

A. `BC:2CE`
B. `2CE:BC`
C. `2BC:CE`
D. `CE:2BC`

Answer

A

Explanation

According to question,

According to figure, when two medians intersects each other in a right angled triangle then we use, this equation,

`rArr 4(BL^(2)+CM^(2))= 5BC^(2)`
`rArr 4 xx (3sqrt(5))/2 + 4CM^(2) = 5BCp^(2)`
`rArr 45 +4CM^(2) = 125`
`rArr CM^(2)=2sqrt(5)` cm