`DeltaABC` तथा `angleDEF` में, AB = DE तथा BC = EF है, तब ज्ञात हुआ की `DeltaABC~=DeltaDEF`, तब।

Options

A. `angleBAC=angleEFD`
B. `angleACB=angleEDF`
C. `angleABC=2angleDEF`
D. `angleABC=angleDEF`

Answer

D

Explanation

According to question,

Given, QA = 3cm
QB=4cm
QC = 5 cm
QD = ?
As we know that
`QD^(2)+(4)^(2)=(3)^(2)+(5)^(2)`
`QD^(2) + 16=9+25)`
`QD^(2)=34-16`
`QD^(2)=34-16`
`QD^(2)=18`
QD=`sqrt(18)`
`QD=3sqrt(2)`