`DeltaABC` में , `angleBAC=75^(@)`, `angleABC=45^(@)` `bar(BC)` को D तब बढ़ाया गया| यदि `angleACD=x^(0)` हे, तब `60^(@)` का `x/3%` ज्ञात करे?

Options

A. `30^(@)`
B. `48^(@)`
C. `15^(@)`
D. `24^(@)`

Answer

D

Explanation

According to question,

Given, `angleA=75^(@)`
`angleB=45^(@)`
`therefore angleACD=angleA+angleB`
`x^(0) = angleACD=120^(@)`
Now, `x/3%` of `60^(@)` is,
`(120/3)%` of `60^(@)`
`=40%` of `60^(@)`
`40/100 xx 60^(@)`
`=24^(@)`