किसी वृत्त के भुजाये `(x^(a)-1), (x^(2)+1)` तथा 2x हे, तब त्रिभुज हे।

Options

A. Equilateral
B. actute angle
C. right-angled
D. isosceles

Answer

C

Explanation

According to question,

Sides AB = `x^(2)-1`
BC=2x
AC=`x^(2)+1`
By pythagoras theorem,
`AC^(2)=AB^(2)+BC^(2)`
`(x^(2)+1)^(2) = (x^(2)-1)^(2)+(2x)^(2)`
`x^(4)+1+2x^(2)=x^(2)+1-2x^(2)+4x^(2)`
`(x^(2)+1)^(2) = (x^(2)+1)^(2)`
`therefore` the triangle is right angle `Delta`