दिए गए चित्र में, `angleONY=50^(@)` और `angleOMY=15^(@)` हे, तब `angleMON` क्या होगा?

Options

A. `30^(@)`
B. `40^(@)`
C. `20^(@)`
D. `70^(@)`

Answer

D

Explanation

According to the figure, OM=OY=ON
`therefore` In `DeltaOMY`
`angleOMY = angleOYM = 15^(@)`
`therefore angleMOY = 180^(@)-15^(@)-15^(@)`
`angleMOY = 150^(@)`
In `DeltaONY`
`angleONY = angleOYN= 50^(@)`
`therefore angleONY = 180^(@)-50^(@)-50^(@)`
`angleNOY = 80^(@)`
`therefore angleMON= 150^(@)-80^(@)`
`angleMON =70^(@)`