In a `DeltaABC`, `angleA + angleB= 118^(@)`, `angleA+angleC=96^(@)`. Find the value of `angleA`. `DeltaABC` me `angleA+angleB=118^(@)`, `angleA+angleC=96^(@)`, `angleA` का मान ज्ञात करे?

Options

A. `36^(@)`
B. `40^(@)`
C. `30^(@)`
D. `34^(@)`

Answer

D

Explanation

According to question,

`angleA + angleB = 118^(@)`
`angleA + angleC = 96^(@)`
`angleA=?`
As we know that
`angleA + angleB+angleC=180^(@)`
`angleC= 180^(@)-118^(@)`
`therefore angleC = 62^(@)`
`angleA = 96^(@)-62^(@)`, `angleA=34^(@)`