`angleA + 1/2 angleB+ angleC=140^(@)`, then `angleB` is `angleA +1/2angleB + angleC=140^(@)`, हे, तब `angleB` हे।

Options

A. `50^(@)`
B. `80^(@)`
C. `40^(@)`
D. `60^(@)`

Answer

B

Explanation

According to question,
`angleA + 1/2 angleB+ angleC = 140^(@)`………….(i)
As we know that
`angleA+angleB+angleC=180^(@)` ……………(iii)
Compare equation (i) and (ii)
`1/2angleB= 40^(@)` `angleB=90^(@)`