नीचे चित्र मे वृत्त की जीवा AB और केंद्र O है | `lt BAT = 50^(@)` के लिए A पर स्पर्शरेखा AT बनाई जाती है | तो `lt ADB`?

Options

A. `120^(@)`
B. `130^(@)`
C. `140^(@)`
D. `150^(@)`

Answer

C

Explanation

Let take a point C on the circumference of circle.
Then `angleBAT = angleBCA = 50^(@)`
(Alternate segment theorem)

In cyclic Quadrilateral ACBD
`angleD = 180^(@)-C`
In a cyclic quadrilateral the sum of opposite angles is `180^(@)`
Then `angleD=180^(@)-50^(@)=130^(@)`