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A ball is thrown upwards from the top of...

A ball is thrown upwards from the top of an incline with angle of projection `theta` with the vertical as shown. Take `theta = 60^(@)` and `g=10 m//s^(2)` . The ball lands exactly at the foot of the incline.

The angle of inclination of incline `alpha` is:

A

`tan^(-1)(3)`

B

`tan^(-1)(6)`

C

`tan^(-1)(sqrt(3)//2)`

D

`tan^(-1)(2//sqrt(3))`

Text Solution

Verified by Experts

The correct Answer is:
D
Horizontal range `=3 xx 10 sin 60^(@) =15 sqrt3m" "tan alpha =(30)/(15sqrt3)=2//sqrt3= alpha=tan^(-1) (2//sqrt3)`
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