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A wedge with a rough groove in the shape...

A wedge with a rough groove in the shape of a quarter of a circle is kept on a smooth table (see figure). A small block is placed in the groove with a small clearance. The wedge is moved with an acceleration`sqrt(3)g` . If the block is to remain stationary relative to groove in the position shown, the coefficient of friction required can be:

A

`(1)/(3)`

B

`(1)/(4)`

C

`(1)/(5)`

D

`(9)/(10)`

Text Solution

Verified by Experts

The correct Answer is:
D
`N cos 30^(@) = mg + f cos 60^(@)`
`N sin 30^(@) + f sin 60^(@) = mg sqrt(3)`
Put `f = mu N` and solve to get `mu = (1)/(sqrt(3))`
This means `mi ge (1)/(sqrt(3))`.
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