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Starting with the same initial condition...

Starting with the same initial conditions, an ideal gas expands from volume `V_1 to V_2` in three different ways. The work done by the gas is W_1 if the process is purely isothermal, `W_2`if purely isobaric and `W_3` if purely adiabatic. Then

A

`W_2 gt W_1 gt W_3`

B

`W_2 gt W_3 gt W_1`

C

`W_1 gt W_2 gt W_3`

D

`W_1 gt W_3 gt W_2`

Text Solution

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The correct Answer is:
A
Work done is equal to area under the curve on PV diagram. (A) is the correct option.
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