A particle starting from rest. Its acceleration (a) versus time (t) is as shown in the figure.
The maximum speed of the particle will be.

Options

A. ` 110ms^(-1)`
B. ` 55 ms^(-1)`
C. ` 550 ms^(-1)`
D. ` 660 ms^(-1)`

Answer

B

Explanation

Till 11s, acceleration is positive, so velocity will go on increasing up to 11s and maximum velocity will happen at 11s.
The area under the acceleration-time graph gives change in velocity. Since particle
Starts with `u=0` change in velocity is `v_f-v_i =v_(max) -0= ` Area under a -t graph or ` V_(max ) =(1)/(2) xx 10 xx 11 = 55ms^(-1)`