Which of the following reaction produce alkane as the product?
I. `R-CO overset(Θ)(O)N overset(o+)(a)+NaOH underset(Delta)overset(CaO)(rarr)`
II. `CH_(3) overset(O)overset("||")(C)CH_(3) underset("conc. HCl")overset(Zn-Hg)(rarr)`
III. `CH_(3)C equiv C CH_(3) overset(LiAlH_(4))(rarr)`
IV. `{:(" "CH_(3)),(" |"),(CH_(3)-C-Cl overset(NaBH_(4))(rarr)),(" |"),(" "CH_(3)):}`

Options

A. I, II, III
B. I, III, IV
C. I, II, IV
D. II, III, IV

Answer

C

Explanation

(I) `R-CO overset(-)(O)overset(+)(NO)+NaOH underset(Delta)overset(CaO)(rarr) underset("(Alkane)")((R-H))`
The mixture of `NaOH+CaO` is called sodalime when it reacts with sodium salt of carboxylic acid, it gives corresponding alkane. The reaction is called decarboxylation of salts of carboxylic acids.
(II) `CH_(3) -underset(O)underset("||")(C)-CH_(3) underset("conc. HCl")overset(Zn-Hg)(rarr)` Alkane
The above reaction is called
Clemmensen-reduction. It coverts aldehydes and ketones to corresponding alkane.
(III) `CH_(3)C equiv C.CH_(3) overset(LiAlH_(4))(rarr)` Alkene
This reaction is used for reduction of alkynes which gives corresponding alkenes.
(IV) `{:(" "CH_(3)" "CH_(3)),(" | |"),(CH_(3)-C-Cl overset(NaBH_(4))(rarr)" alkane, i.e. "CH_(3)-C-H),(" | |"),(" "CH_(3)" "CH_(3)):}`
Hence, option (c) is the correct answer.