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The molality (in mol kg^(-1) ) of 1 mol...

The molality (in mol `kg^(-1)` ) of 1 mole of solute in 50 g of solvent is :

A

10

B

20

C

30

D

40

Text Solution

Verified by Experts

The correct Answer is:
B
Given,
Moles of solute `(n)=1` mol
Mass of solvent `(w_(A))=50` g
`:'` Molality `(m)=(nxx1000)/(w_(A)"(in g)")`
`:. m=1000/50=20" mol kg"^(-1)`
Hence, option (b) is the correct answer.
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