Statement(A): Sulphur vapour is paramagnetic .
Statement (B): Reaction of dil. HCl with finely divided forms `FeCl_3` and `H_2` gas.

Options

A. Statement (A) is correct, but (B) is wrong.
B. Both the Statement are correct
C. Statement (A) is wrong, but (B) is correct
D. Both the statement are wrong

Answer

A

Explanation

Statement (A) Sulphur vapour is paramagnetic is correct statement as sulphur vapour has formula `S_(2)`, i.e. similar to `O_(2)` and `O_(2)` has two unpaired electrons in its anti-bonding molecular orbitals.
Statement (B) Reaction of HCl (dil.) with finely divided iron forms `FeCl_(3)` and `H_(2)` gas is a wrong statement as the whole reaction is as follows :
`Fe+2HCl ("dil.") rarr FeCl_(2)+H_(2)(g)`
The `H_(2)(g)` produced will prevent the formation of `Fe^(3+)` (i.e. `FeCl_(3)`).
Hence, option (a) is the correct answer.