Match the following
`{:(,"List I",,"List II"),(,,,"(Major"),(,,,"Product)"),((A),CH_(3)-CHBr-CH_(2)Broverset(KOH//C_(2)H_(5)OH)(rarr),(I),1^(@)-"alkyl bromide"),((B),CH_(3)-CH_(2)-CH = CH_(2)underset((C_(6)H_(5)CO)_(2)O_(2)", "Delta)overset(HBr)(rarr),(II),2^(@)-"alkyl bromide"),((C),CH_(3)CH_(2)CH_(3) overset(Br_(2), hv)(rarr),(III),"Allyl bromide"),((D),CH_(3)-CH=CH_(2) underset(Delta)overset(NBS)(rarr),(IV),"Alkenyl bromide"):}`
the correct answer is

Options

A. `{:("A","B","C","D"),(I,IV,II,III):}`
B. `{:("A","B","C","D"),(IV,III,I,II):}`
C. `{:("A","B","C","D"),(II,III,I,IV):}`
D. `{:("A","B","C","D"),(IV,I,II,III):}`

Answer

D

Explanation

(A) `CH_(3)-CHBr-CH_(2)Br overset(KOH//C_(2)H_(5)OH)(rarr) (IV)` Alkenyl bromide.
`:' KOH` (alc.)will remove one H and one Br to give alkenyl bromide.
(B) `CH_(3)-CH_(2)-CH=CH_(2) underset((C_(6)H_(5)CO)_(2)O_(2), Delta)overset(HBr)(rarr) (I)`
give `1^(@)` alkyl bromide due to presence of peroxide and HBr. (anti-markownikoff's addition)
(C) `CH_(3)-CH_(2)-CH_(3) overset(Br_(2), hv)(rarr) (II)`, gives `2^(@)` alkyl bromide brcause `2^(@)` carbocation is more stable.
(D) `CH_(3)-CH=CH_(2) overset(NBS)(rarr) (III)` gives allyl bromide due to presence of NBS.
Hence, option (d) is the correct answer.