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The vertex of the parabola (y-1)^2 =8 (x...

The vertex of the parabola `(y-1)^2 =8 (x-1)` is at the centre of a circle and the parabola cuts that circle at the ends of its latusrectum. Then the equation of that circle is

A

`x^2+y^2 -2x -2y -18 =0`

B

`x^2+y^2 -2x-2y +18=0`

C

`x^2+y^2+2x+2y-16 =0`

D

`x^2+y^2-2x-2y+16 =0`

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A
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