Find the potential difference between a and b as shown in the below circuit,

Options

A. 165 V
B. 198 V
C. 213 V
D. 224 V

Answer

C

Explanation

The circuit can be radrawn as

45V is drop across the branch one, so currect throught it,
`I_1 = (45)/(R_(eq1))=(45)/((15)/4) = 12 A`
Now, above circuit can be redrawn as ,

Sicne in a series circuit , the current flows will be same,
hence, `V_(ab) = I _(ab) R_(eq)(ab) = 12 ((15)/4+4 +10)`
`rArr V_(ab) = 213 V`