While combusting in air , 4g of `H_2` was completely converted into water. If `36 mu` mole of `CO_2` from air is dissolved into that water, what is the concentration of `CO_2 ` ?

Options

A. `1 mu M`
B. `1 mM`
C. 1 nM
D. 1000 mM

Answer

B

Explanation

The equation takes place as follows :
`{:(2H_2+O_2rarr),(4g):}{:(2H_2O),(36g):}`
`:'"36 g of "CO_2" is dissolved in 36 g of "H_2O.`
`:."Conc.of "CO_2=(36xx10^(-6)xx10^3)/36=( :."conc.(C)"=n/v)`
`10^(-3)M=1mM`
Hence, option (b) is the correct answer.