The approximate molarity of a solution in mol `L ^(-1)` that contains `13.50` g of naCl dissolved in 452 mL of water is

Options

A. 0.25
B. 0.51
C. 1
D. 1.2

Answer

B

Explanation

Given,
Mass of NaCl = 13.5 g
Volume of solution = 452mL
Molarity of solution (M)
` = ("Mass of NaCl")/("Molar mass of NaCl") xx (1)/(" Volume of solution in (L)")`
`M = (13.50)/(58.5) xx 1000/452 "mol/L" rArr M = 0.51 ` mol/L