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Consider the single electrode process 4H...

Consider the single electrode process `4H^ + 4e^- = 2H_2` catalyzed by platinum black electrode in HCl electrolyte. The potential of the electrode is -0.059V Vs. SHE. What is the concenteration of the acid in the hydrogen half cell if the `H_2` pressure is 1 bar?

A

1m

B

10m

C

0.1m

D

0.01m

Text Solution

Verified by Experts

The correct Answer is:
C
`4H^(+)+4e^(-) hArr 2H_2`
`E = E^(@) -(0.059)/( n ) log (pH_2)/([H^+]^4)`
` -0.059 =0-(0.059)/(4) log (1)/([H^+]^4)`
` = [H^+]=10^(-1 ) =0.1 M`
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