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Given Delta Hr ^@ for CO2(g) , CO(g) and...

Given `Delta H_r ^@` for `CO_2(g) , CO_(g) and H_2O(g)` are -393.5, -110.5 and -241.8 `KJ mol^-1` respectively. The `Delta H_r^@ (in KJ mol^-1]` for the reaction
`CO_2(g) + H_2(g) rightarrow CO_(g) + H_2O(g)` is

A

`524.1`

B

`-262.5`

C

`-41.7`

D

`41.2`

Text Solution

Verified by Experts

The correct Answer is:
D
`CO_2 (g) +H_2 (g) +H_2 (g) to CO(g) +H_2 O(g) `
` Delta H_(t) ^(@ ) =(Delta H) _("product") - ( Delta H)_("Reaction")`
Hence `Delta H_(f)^(@) = [ Delta H_(fco _2 (s) )=-393.5 kj mol ^(-1)`
` Delta H_(f CO )^(@)(s) 110.5 kj mol ^(-1)`
` Delta H_(fH_2 O)^(@)=- 241.8 kj mol ^(-1)`
Put there value in equation (i)
` Delta H_(f^@)=-110.5 -2418 + 393.5 =412`
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