4q^(3)-6q^(2)-4q+3;2q-1

Let the polynomials be (1) -13q^(5) + 4q^(2) + 12q (2) (x^(2) + 4 ) ( x^(2) + 9) (3) 4q^(8) - q^(6) + q^(2) (4) - ( 5)/( 7) y^(12) + y^(3) + y^(5) Then ascending order of their degree is

Show that : (4p q+3q)^2-(4q p-3q)^2=48 p q^2 (a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0

2p+3q=18 and 4p^(2)+4pq-3q^(2)-36=0 then what is (2p+q) equal to?

Simplify ((q^(3-7)q xx q^(6-2q))/(q^(2q)xx q^(9-2q)))^((1)/(9))

If q_(1),q_(2),q_(3) ar rootsof the equation x^(3)+64=0 then value of |{:(q_(1),q_(2),q_(3)),(q_(2),q_(3),q_(1)),(q_(3),q_(1),q_(2)):}|

If q_(1),q_(2),q_(3) ar rootsof the equation x^(3)+64=0 then value of |{:(q_(1),q_(2),q_(3)),(q_(2),q_(3),q_(1)),(q_(3),q_(1),q_(2)):}|