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The average kinetic energy of one molecu...

The average kinetic energy of one molecule of an ideal gas at `27^@`C and 1 atm pressure is

A

`900 cal K^(-1) mol^(-1)`

B

`6.21 xx IO^(2)' JK^(-1) mol ecu l e^(-1)`

C

`336.7 JK^(-1) mol ecu l e^(-1)`

D

`3741.3 JK ^(-1)mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
b
Average kinetic energy of single molecule = `3/2 R/N_(0) T`
`3/2 xx 8.314/(6.023 xx 10^(23)) xx(27+273)`
`= 6.211xx10^(-21)JK^(-1) mol ecul e^(-1)`
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