At `27^@`C, 500 mL of helium diffuses in 30 min. What is the time (in hours) taken for 1000 mL of `SO_(2)` to diffuse under same experimental conditions ?

Options

A. 240
B. 3
C. 2
D. 4

Answer

d

Explanation

`r_(He)=500/300 ml//min, r_(SO_(2))=1000/t`
According to Graham's law,
`r_(He)/= r_(SO_(2))=sqrt(M_(SO_(2))/M_(He))`
`implies 500/300 t/1000 =sqrt(64/4)`
`implies t/60=4`
`therefore t=60xx4 = 240 mins=`4 hrs