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4 g of an ideal gas occupies 5.6035 L of...

4 g of an ideal gas occupies 5.6035 L of volume at 546 K and 2 atm pressure. What is its molecular weight ?

A

4

B

16

C

32

D

64

Text Solution

Verified by Experts

The correct Answer is:
b

W = 4g, V = 5.6035L, T = 546 K, P = 2 atm
Ideal gas equation,
PV = nRT
`2 xx 5.6035 = 4/GMW xx 0.0821 xx 546 [ because n= (Wt)/(GMW)]`
`implies GMW = (4 xx 0.0821 xx 546)/(2 xx 5.6035)`
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