A gaseous mixture contains 56g of `N_(2)`, 44g of `CO_(2)` and 16g of `CH_(4)`. The total pressure of the mixture is 720 mm Hg. The partial pressure of `CH_(4)` is

Options

A. 180 mm
B. 360 mm
C. 540 mm
D. 720 mm

Answer

a

Explanation

Number of moles of `N_(2) = 56/28 = 2`
Number of moles of `CO_(2) = 44/44 = 1`
Number of moles of `CH_(4) =16/16 = 1`
Total no of moles = 2 + 1 + 1 = 4
`therefore` Partial pressure of `CH_(4)``= 1/4 xx 720 - 180 mm Hg`.