The factor by which the kinetic energy of 8g of H, at 2`7^@`C is greater than the kinetic energy of 8g of `O_(2)` at the same temperature, is

Options

A. 4
B. 8
C. 16
D. 32

Answer

c

Explanation

Kinetic energy, `KE = 3/2 nRT`
i.e., `(KE_(1))/(KE_(2))=n_(1)/n_(2)`
No. of moles of `H_(2) = 8/2 = 4`
No. of moles of `O_(2) = 8/32 = ¼`
`therefore (KE_(1))/(KE_(2)) = 4/(1/4)=16`