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The weight of oxalic acid crystals,H(2)C...

 The weight of oxalic acid crystals,`H_(2)C_(2)O_(4)2H_(2)O` required to prepare 500 ml of 0.2 N solution is,

A

`3.4g`

B

`63g`

C

`6.3g`

D

`126g`

Text Solution

Verified by Experts

The correct Answer is:
(c)
Volume of solution (V) = 500 mL
Normality of solution (N) = 0.2
Molecular weight of `H_(2)C_(2)O_(4) 2H_(2)O (m) = 2+24+64 +36=126_(g)`
Equivalent weightof`H_(2)C_(2)O_(4)2H_(2)O(E) =(m)/(2)=(126)/(2) = 63g`
`w= (NEV)/(1000)=(0.2xx63xx500)/(1000)`
`therefore Weight of H_(2)C_(2)O_(4)2H_(2)O= 6.3 g`
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