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If tan 20^@ = lambda, then (tan160^@ - t...

If `tan 20^@ = lambda`, then `(tan160^@ - tan 110^@)/(1+ (tan 160^@)(tan110^@)` =

A

`(1+lambda^2)/(2lambda)`

B

`(1+lambda^2)/lambda`

C

`(1-lambda^2)/lambda`

D

`(1-lambda^2)/(2lambda)`

Text Solution

Verified by Experts

The correct Answer is:
D
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