A simple pendulum of length 1 m is freely suspended from the ceiling of an elevator the time period of small oscollations as the elevator moves up with an acceleration of `2m//s ^2 ` is ( use ` g=10 m//s ^2)`

Options

A. `pi/sqrt5`s
B. `sqrt(2/5pi)s`
C. `pi/sqrt2`s
D. `pi/sqrt3`s

Answer

D

Explanation

Answer (4) Length, l = 1m Acceleration, a = `2m/s^2 g= 10m/s^2`
Time period, `T = 2pisqrt(1/(g+a)) .
= 2pisqrt(1/(10+2)) .
= 2pisqrt(1/12) therefore T = pi/sqrt3 sec`